Ok.. but that doesn't really help me make sure your circuit will do what you want
Here's what I gather from the circuit diagram you've provided:
When the rocker switch is off:
the HDD 3.3V signal will power the LED directly. (through the normally closed pin of relay 1) [if 3.3V = on, LED = on]
the CCFL inverter will receive 12V constantly. (through the normally closed pin of relay 2) [CCFL = on]
When the rocker switch is on:
the 5V power from the rocker switch will power the LED directly. (through relay 1 signal pin) [LED = on]
the CCFL inverter will receive an
inverted version of the HDD signal. (through relay 2 normally closed pin) [if 3.3V = on, CCFL = off, else CCFL = on]
At the moment, relay 3 (far right) does nothing. If the goal of relay 3 was to turn off the CCFL by grounding it, this is unnecessary. Simply disconnect anything from the normally open pin of relay 2. That way, when relay 2 is on, nothing powers the CCFL, and it turns off.
Also, unless the specific relay you're looking at requires them, none of the diodes in the diagram are needed.
One last thing. Instead of the diode above relay 1 (in green), that should probably be a resistor instead. If the LED will be driven by 3.3V directly, you will probably want a resistor to drop the 5V from the rocker switch to 3.3V so that you don't damage the LED, and so that there is as little visual difference in brightness as possible.
Revised Diagram:
To be clear, what the above does is this:
IF Rocker Switch = OFF
CCFL = ON constant
LED = HDD 3.3V
IF Rocker Switch = OFF
LED = ON constant
CCFL = INVERTED HDD 3.3V (CCFL off when HDD on, CCFL on when HDD off)