C++ Study Help? [solved]

[Lastpilot]

Given the function definition

void Test (/* in */ int alpha)
    {
      static int n = 5;
      n = n + alpha;
      cout << n << ' ';
    }

what is the output of the following code? (assume Test has not been called previously)
Test (20);
Test (30);

The answer is 25 55.....why isnt it just 25 35?

[hashbaz]

static.  It remembers.

[metalliqaz]

static.  It remembers.

What he said.

[Lastpilot]

So does that mean that the "= 5" part doesn't matter on the second function call?

[metalliqaz]

Yes, once it is initialized it doesn't get initialized again.

[Lastpilot]

Ah okay I get it. Thanks guys!

[hashbaz]

Note that reinitializing n each time would defeat the purpose of declaring it to be static.  It would have no way to retain its value between calls.

[jalaj]

static int n = 5  /* or just use int n = 5 */

void Test (/* in */ int alpha)
    { 
      alpha = n + alpha;
      cout << alpha << ' ';
    }

that should return what you're looking for
test(20) -> 25
test(30) -> 35

[metalliqaz]

That is not correct code.