This is not possible using normal techniques. The click comes from added energy that is released. Since the energy is harvested from the key travel, then it must have hysterisis. The amount of energy released in the click being proportional to the "area" of hysteresis.
As I understand it, hysteresis in switches means that the reset point is higher than the actuation point. i.e. you can't "hover" around the actuation point and repeatedly actuate and release the switch with only the tiniest of movement.
Now it's also true that clicky switches will tend to "catapult" the slider downwards when the clicker energy is released, but in Alps- and SMK-type switches this has no bearing on hysteresis. When you release the switch back up to the pretravel distance, the contacts will open. It's not all that hard to press a clicky switch lightly enough that it will actuate but not bottom out; with Cherry MX blue and buckling spring, easing up a little bit won't release the contacts, but with an Alps- or SMK-type switch (including Omron, KPT etc) it will.
As to why Cherry went to so much trouble to achieve hysteresis, I have no idea, especially as the lack of it doesn't seem to cause a problem for other switches. With buckling spring, I guess it's just that the spring won't snap back into position at the same point where it buckled; whether this was intended, I don't know.
So based on how my head is wrapping around the mechanism of the Monterey switches, would it be possible to have a clicky linear switch?
It would be very hard. A click requires building up and releasing force, and you would need to do that in such a way that you can't feel it. The best I can think of would be to build up this energy when the key returns home, such that depressing the key only triggers the click, without needing to "charge" it first. The switch wouldn't be linear on the upstroke, but you're far less likely to notice that. You may also need a more powerful return spring to charge the clicker, potentially resulting in a stiffer switch.