i suck at math

[Computer-Lab in Basement]

so is there any way to solve for p in this equation?

p=(g*p)+c

p is on both sides, so i'm guessing no?

[aznairjordan]

i think this is how you do it, I'm out of college now so everything is rusty

p=gp+c
0=gp+c-p
0=(gp-p)+c
0=(g-1)p+c
-c=(g-1)p
-c/(g-1)=p

[azhdar]

Divide per p:

1= g+c/p
1-g=c/p

not sure if that's helping.

[fliptrik]

i think this is how you do it, I'm out of college now so everything is rusty

p=gp+c
0=gp+c-p
0=(gp-p)+c
0=(g-1)p+c
-c=(g-1)p
-c/(g-1)=p

This one is correct, I believe. -c/(g-1) where g ≠ 1.

[Computer-Lab in Basement]

i think this is how you do it, I'm out of college now so everything is rusty

p=gp+c
0=gp+c-p
0=(gp-p)+c
0=(g-1)p+c
-c=(g-1)p
-c/(g-1)=p

how did you get from the second line to the third line? i'm confused...

[hwood34]

i think this is how you do it, I'm out of college now so everything is rusty

p=gp+c
0=gp+c-p
0=(gp-p)+c
0=(g-1)p+c
-c=(g-1)p
-c/(g-1)=p

how did you get from the second line to the third line? i'm confused...

just think of the minus p like a negative p that you can move around. He's just moving it so he can pull out the "p" from both "p" and "gp" so there's only 1 "p"

[aznairjordan]

i think this is how you do it, I'm out of college now so everything is rusty

p=gp+c
0=gp+c-p
0=(gp-p)+c
0=(g-1)p+c
-c=(g-1)p
-c/(g-1)=p

how did you get from the second line to the third line? i'm confused...

i just grouped together the p terms in parentheses. so from the second to third step it is basically this.

0=gp+c-1*p
0=gp-1*p+c    Rearranged
0=(gp-1*p)+c   Parentheses
0=(g-1)*p+c

[Computer-Lab in Basement]

i think this is how you do it, I'm out of college now so everything is rusty

p=gp+c
0=gp+c-p
0=(gp-p)+c
0=(g-1)p+c
-c=(g-1)p
-c/(g-1)=p

how did you get from the second line to the third line? i'm confused...

just think of the minus p like a negative p that you can move around. He's just moving it so he can pull out the "p" from both "p" and "gp" so there's only 1 "p"

ok that makes sense, thanks

[Computer-Lab in Basement]

thanks for the help guys, my boss is happy...

[hwood34]

thanks for the help guys, my boss is happy...

[paicrai]

is this what math is like
****in hell meth sounds like more fun than this

[tp4tissue]

Computer lab..  how old are ya..  please tell me..

[tp4tissue]

are you trolling us ...      I thought you were  programmer by trade.. 

[tp4tissue]

Divide per p:

1= g+c/p
1-g=c/p

not sure if that's helping.

This is exactly the same as the answer above you by (aznairjordon) if you pull a negative 1 from (1-g)

[neverused]

thanks for the help guys, my boss is happy...

You got paid to figure that out?

I'd happily be your company's contract remedial algebra consultant.

[tp4tissue]

thanks for the help guys, my boss is happy...

You got paid to figure that out?

I'd happily be your company's contract remedial algebra consultant.

Don't listen to this mean-ee Computer Labz...


Math is good for u and fun 2 learn..

[neverused]

thanks for the help guys, my boss is happy...

You got paid to figure that out?

I'd happily be your company's contract remedial algebra consultant.

Don't listen to this mean-ee Computer Labz...


Math is good for u and fun 2 learn..

That's why I offered to consult, perhaps tutoring would be better.